Intro to property based tests
Some companies will ask you to do the Roman Numeral Kata as part of the interview process. This chapter will show how you can tackle it with TDD.
We are going to write a function which converts an Arabic number (numbers 0 to 9) to a Roman Numeral.
You build them by sticking symbols together and those symbols represent numbers
So
I is "one". III is three.Seems easy but there's a few interesting rules.
V means five, but IV is 4 (not IIII).MCMLXXXIV is 1984. That looks complicated and it's hard to imagine how we can write code to figure this out right from the start.As this book stresses, a key skill for software developers is to try and identify "thin vertical slices" of useful functionality and then iterating. The TDD workflow helps facilitate iterative development.
So rather than 1984, let's start with 1.
func TestRomanNumerals(t *testing.T) {
got := ConvertToRoman(1)
want := "I"
if got != want {
t.Errorf("got %q, want %q", got, want)
}
}
If you've got this far in the book this is hopefully feeling very boring and routine to you. That's a good thing.
./numeral_test.go:6:9: undefined: ConvertToRomanLet the compiler guide the way
Create our function but don't make the test pass yet, always make sure the tests fails how you expect
func ConvertToRoman(arabic int) string {
return ""
}
It should run now
=== RUN TestRomanNumerals
--- FAIL: TestRomanNumerals (0.00s)
numeral_test.go:10: got '', want 'I'
FAIL
func ConvertToRoman(arabic int) string {
return "I"
}
Not much to refactor yet.
I know it feels weird just to hard-code the result but with TDD we want to stay out of "red" for as long as possible. It may feel like we haven't accomplished much but we've defined our API and got a test capturing one of our rules; even if the "real" code is pretty dumb.
Now use that uneasy feeling to write a new test to force us to write slightly less dumb code.
We can use subtests to nicely group our tests
func TestRomanNumerals(t *testing.T) {
t.Run("1 gets converted to I", func(t *testing.T) {
got := ConvertToRoman(1)
want := "I"
if got != want {
t.Errorf("got %q, want %q", got, want)
}
})
t.Run("2 gets converted to II", func(t *testing.T) {
got := ConvertToRoman(2)
want := "II"
if got != want {
t.Errorf("got %q, want %q", got, want)
}
})
}
=== RUN TestRomanNumerals/2_gets_converted_to_II
--- FAIL: TestRomanNumerals/2_gets_converted_to_II (0.00s)
numeral_test.go:20: got 'I', want 'II'
Not much surprise there
func ConvertToRoman(arabic int) string {
if arabic == 2 {
return "II"
}
return "I"
}
Yup, it still feels like we're not actually tackling the problem. So we need to write more tests to drive us forward.
We have some repetition in our tests. When you're testing something which feels like it's a matter of "given input X, we expect Y" you should probably use table based tests.
func TestRomanNumerals(t *testing.T) {
cases := []struct {
Description string
Arabic int
Want string
}{
{"1 gets converted to I", 1, "I"},
{"2 gets converted to II", 2, "II"},
}
for _, test := range cases {
t.Run(test.Description, func(t *testing.T) {
got := ConvertToRoman(test.Arabic)
if got != test.Want {
t.Errorf("got %q, want %q", got, test.Want)
}
})
}
}
We can now easily add more cases without having to write any more test boilerplate.
Let's push on and go for 3
Add the following to our cases
{"3 gets converted to III", 3, "III"},
=== RUN TestRomanNumerals/3_gets_converted_to_III
--- FAIL: TestRomanNumerals/3_gets_converted_to_III (0.00s)
numeral_test.go:20: got 'I', want 'III'
func ConvertToRoman(arabic int) string {
if arabic == 3 {
return "III"
}
if arabic == 2 {
return "II"
}
return "I"
}
OK so I'm starting to not enjoy these if statements and if you look at the code hard enough you can see that we're building a string of
I based on the size of arabic.We "know" that for more complicated numbers we will be doing some kind of arithmetic and string concatenation.
Let's try a refactor with these thoughts in mind, it might not be suitable for the end solution but that's OK. We can always throw our code away and start afresh with the tests we have to guide us.
func ConvertToRoman(arabic int) string {
var result strings.Builder
for i:=0; i<arabic; i++ {
result.WriteString("I")
}
return result.String()
}
A Builder is used to efficiently build a string using Write methods. It minimizes memory copying.
Normally I wouldn't bother with such optimisations until I have an actual performance problem but the amount of code is not much larger than a "manual" appending on a string so we may as well use the faster approach.
The code looks better to me and describes the domain as we know it right now.
Things start getting more complicated now. The Romans in their wisdom thought repeating characters would become hard to read and count. So a rule with Roman Numerals is you can't have the same character repeated more than 3 times in a row.
Instead you take the next highest symbol and then "subtract" by putting a symbol to the left of it. Not all symbols can be used as subtractors; only I (1), X (10) and C (100).
For example
5 in Roman Numerals is V. To create 4 you do not do IIII, instead you do IV.{"4 gets converted to IV (can't repeat more than 3 times)", 4, "IV"},
=== RUN TestRomanNumerals/4_gets_converted_to_IV_(cant_repeat_more_than_3_times)
--- FAIL: TestRomanNumerals/4_gets_converted_to_IV_(cant_repeat_more_than_3_times) (0.00s)
numeral_test.go:24: got 'IIII', want 'IV'
func ConvertToRoman(arabic int) string {
if arabic == 4 {
return "IV"
}
var result strings.Builder
for i:=0; i<arabic; i++ {
result.WriteString("I")
}
return result.String()
}
I don't "like" that we have broken our string building pattern and I want to carry on with it.
func ConvertToRoman(arabic int) string {
var result strings.Builder
for i := arabic; i > 0; i-- {
if i == 4 {
result.WriteString("IV")
break
}
result.WriteString("I")
}
return result.String()
}
In order for 4 to "fit" with my current thinking I now count down from the Arabic number, adding symbols to our string as we progress. Not sure if this will work in the long run but let's see!
Let's make 5 work
{"5 gets converted to V", 5, "V"},
=== RUN TestRomanNumerals/5_gets_converted_to_V
--- FAIL: TestRomanNumerals/5_gets_converted_to_V (0.00s)
numeral_test.go:25: got 'IIV', want 'V'
Just copy the approach we did for 4
func ConvertToRoman(arabic int) string {
var result strings.Builder
for i := arabic; i > 0; i-- {
if i == 5 {
result.WriteString("V")
break
}
if i == 4 {
result.WriteString("IV")
break
}
result.WriteString("I")
}
return result.String()
}
Repetition in loops like this are usually a sign of an abstraction waiting to be called out. Short-circuiting loops can be an effective tool for readability but it could also be telling you something else.
We are looping over our Arabic number and if we hit certain symbols we are calling
break but what we are really doing is subtracting over i in a ham-fisted manner.func ConvertToRoman(arabic int) string {
var result strings.Builder
for arabic > 0 {
switch {
case arabic > 4:
result.WriteString("V")
arabic -= 5
case arabic > 3:
result.WriteString("IV")
arabic -= 4
default:
result.WriteString("I")
arabic--
}
}
return result.String()
}
- Given the signals I'm reading from our code, driven from our tests of some very basic scenarios I can see that to build a Roman Numeral I need to subtract from
arabicas I apply symbols - The
forloop no longer relies on aniand instead we will keep building our string until we have subtracted enough symbols away fromarabic.
I'm pretty sure this approach will be valid for 6 (VI), 7 (VII) and 8 (VIII) too. Nonetheless add the cases in to our test suite and check (I won't include the code for brevity, check the github for samples if you're unsure).
9 follows the same rule as 4 in that we should subtract
I from the representation of the following number. 10 is represented in Roman Numerals with X; so therefore 9 should be IX.{"9 gets converted to IX", 9, "IX"}
=== RUN TestRomanNumerals/9_gets_converted_to_IX
--- FAIL: TestRomanNumerals/9_gets_converted_to_IX (0.00s)
numeral_test.go:29: got 'VIV', want 'IX'
We should be able to adopt the same approach as before
case arabic > 8:
result.WriteString("IX")
arabic -= 9
It feels like the code is still telling us there's a refactor somewhere but it's not totally obvious to me, so let's keep going.
I'll skip the code for this too, but add to your test cases a test for
10 which should be X and make it pass before reading on.Here are a few tests I added as I'm confident up to 39 our code should work
{"10 gets converted to X", 10, "X"},
{"14 gets converted to XIV", 14, "XIV"},
{"18 gets converted to XVIII", 18, "XVIII"},
{"20 gets converted to XX", 20, "XX"},
{"39 gets converted to XXXIX", 39, "XXXIX"},
If you've ever done OO programming, you'll know that you should view
switch statements with a bit of suspicion. Usually you are capturing a concept or data inside some imperative code when in fact it could be captured in a class structure instead.Go isn't strictly OO but that doesn't mean we ignore the lessons OO offers entirely (as much as some would like to tell you).
Our switch statement is describing some truths about Roman Numerals along with behaviour.
We can refactor this by decoupling the data from the behaviour.
type RomanNumeral struct {
Value int
Symbol string
}
var allRomanNumerals = []RomanNumeral {
{10, "X"},
{9, "IX"},
{5, "V"},
{4, "IV"},
{1, "I"},
}
func ConvertToRoman(arabic int) string {
var result strings.Builder
for _, numeral := range allRomanNumerals {
for arabic >= numeral.Value {
result.WriteString(numeral.Symbol)
arabic -= numeral.Value
}
}
return result.String()
}
This feels much better. We've declared some rules around the numerals as data rather than hidden in an algorithm and we can see how we just work through the Arabic number, trying to add symbols to our result if they fit.
Does this abstraction work for bigger numbers? Extend the test suite so it works for the Roman number for 50 which is
L.Here are some test cases, try and make them pass.
{"40 gets converted to XL", 40, "XL"},
{"47 gets converted to XLVII", 47, "XLVII"},
{"49 gets converted to XLIX", 49, "XLIX"},
{"50 gets converted to L", 50, "L"},
Here are the remaining symbols
Arabic | Roman |
100 | C |
500 | D |
1000 | M |
Take the same approach for the remaining symbols, it should just be a matter of adding data to both the tests and our array of symbols.
Does your code work for
1984: MCMLXXXIV ?Here is my final test suite
func TestRomanNumerals(t *testing.T) {
cases := []struct {
Arabic int
Roman string
}{
{Arabic: 1, Roman: "I"},
{Arabic: 2, Roman: "II"},
{Arabic: 3, Roman: "III"},
{Arabic: 4, Roman: "IV"},
{Arabic: 5, Roman: "V"},
{Arabic: 6, Roman: "VI"},
{Arabic: 7, Roman: "VII"},
{Arabic: 8, Roman: "VIII"},
{Arabic: 9, Roman: "IX"},
{Arabic: 10, Roman: "X"},
{Arabic: 14, Roman: "XIV"},
{Arabic: 18, Roman: "XVIII"},
{Arabic: 20, Roman: "XX"},
{Arabic: 39, Roman: "XXXIX"},
{Arabic: 40, Roman: "XL"},
{Arabic: 47, Roman: "XLVII"},
{Arabic: 49, Roman: "XLIX"},
{Arabic: 50, Roman: "L"},
{Arabic: 100, Roman: "C"},
{Arabic: 90, Roman: "XC"},
{Arabic: 400, Roman: "CD"},
{Arabic: 500, Roman: "D"},
{Arabic: 900, Roman: "CM"},
{Arabic: 1000, Roman: "M"},
{Arabic: 1984, Roman: "MCMLXXXIV"},
{Arabic: 3999, Roman: "MMMCMXCIX"},
{Arabic: 2014, Roman: "MMXIV"},
{Arabic: 1006, Roman: "MVI"},
{Arabic: 798, Roman: "DCCXCVIII"},
}
for _, test := range cases {
t.Run(fmt.Sprintf("%d gets converted to %q", test.Arabic, test.Roman), func(t *testing.T) {
got := ConvertToRoman(test.Arabic)
if got != test.Roman {
t.Errorf("got %q, want %q", got, test.Roman)
}
})
}
}
- I removed
descriptionas I felt the data described enough of the information. - I added a few other edge cases I found just to give me a little more confidence. With table based tests this is very cheap to do.
I didn't change the algorithm, all I had to do was update the
allRomanNumerals array.var allRomanNumerals = []RomanNumeral{
{1000, "M"},
{900, "CM"},
{500, "D"},
{400, "CD"},
{100, "C"},
{90, "XC"},
{50, "L"},
{40, "XL"},
{10, "X"},
{9, "IX"},
{5, "V"},
{4, "IV"},
{1, "I"},
}
We're not done yet. Next we're going to write a function that converts from a Roman Numeral to an
intWe can re-use our test cases here with a little refactoring
Move the
cases variable outside of the test as a package variable in a var block.func TestConvertingToArabic(t *testing.T) {
for _, test := range cases[:1] {
t.Run(fmt.Sprintf("%q gets converted to %d", test.Roman, test.Arabic), func(t *testing.T) {
got := ConvertToArabic(test.Roman)
if got != test.Arabic {
t.Errorf("got %d, want %d", got, test.Arabic)
}
})
}
}
Notice I am using the slice functionality to just run one of the tests for now (
cases[:1]) as trying to make all of those tests pass all at once is too big a leap./numeral_test.go:60:11: undefined: ConvertToArabic
Add our new function definition
func ConvertToArabic(roman string) int {
return 0
}
The test should now run and fail
--- FAIL: TestConvertingToArabic (0.00s)
--- FAIL: TestConvertingToArabic/'I'_gets_converted_to_1 (0.00s)
numeral_test.go:62: got 0, want 1
You know what to do
func ConvertToArabic(roman string) int {
return 1
}
Next, change the slice index in our test to move to the next test case (e.g.
cases[:2]). Make it pass yourself with the dumbest code you can think of, continue writing dumb code (best book ever right?) for the third case too. Here's my dumb code.func ConvertToArabic(roman string) int {
if roman == "III" {
return 3
}
if roman == "II" {
return 2
}
return 1
}
Through the dumbness of real code that works we can start to see a pattern like before. We need to iterate through the input and build something, in this case a total.
func ConvertToArabic(roman string) int {
total := 0
for range roman {
total++
}
return total
}
Next we move to
cases[:4] (IV) which now fails because it gets 2 back as that's the length of the string.// earlier..
type RomanNumerals []RomanNumeral
func (r RomanNumerals) ValueOf(symbol string) int {
for _, s := range r {
if s.Symbol == symbol {
return s.Value
}
}
return 0
}
// later..
func ConvertToArabic(roman string) int {
total := 0
for i := 0; i < len(roman); i++ {
symbol := roman[i]
// look ahead to next symbol if we can and, the current symbol is base 10 (only valid subtractors)
if i+1 < len(roman) && symbol == 'I' {
nextSymbol := roman[i+1]
// build the two character string
potentialNumber := string([]byte{symbol, nextSymbol})
// get the value of the two character string
value := allRomanNumerals.ValueOf(potentialNumber)
if value != 0 {
total += value
i++ // move past this character too for the next loop
} else {
total++
}
} else {
total++
}
}
return total
}
This is horrible but it does work. It's so bad I felt the need to add comments.
- I wanted to be able to look up an integer value for a given roman numeral so I made a type from our array of
RomanNumerals and then added a method to it,ValueOf - Next in our loop we need to look ahead if the string is big enough and the current symbol is a valid subtractor. At the moment it's just
I(1) but can also beX(10) orC(100).- If it satisfies both of these conditions we need to lookup the value and add it to the total if it is one of the special subtractors, otherwise ignore it
- Then we need to further increment
iso we don't count this symbol twice
I'm not entirely convinced this will be the long-term approach and there's potentially some interesting refactors we could do, but I'll resist that in case our approach is totally wrong. I'd rather make a few more tests pass first and see. For the meantime I made the first
if statement slightly less horrible.func ConvertToArabic(roman string) int {
total := 0
for i := 0; i < len(roman); i++ {
symbol := roman[i]
if couldBeSubtractive(i, symbol, roman) {
nextSymbol := roman[i+1]
// build the two character string
potentialNumber := string([]byte{symbol, nextSymbol})
// get the value of the two character string
value := allRomanNumerals.ValueOf(potentialNumber)
if value != 0 {
total += value
i++ // move past this character too for the next loop
} else {
total++
}
} else {
total++
}
}
return total
}
func couldBeSubtractive(index int, currentSymbol uint8, roman string) bool {
return index+1 < len(roman) && currentSymbol == 'I'
}
Let's move on to
cases[:5]=== RUN TestConvertingToArabic/'V'_gets_converted_to_5
--- FAIL: TestConvertingToArabic/'V'_gets_converted_to_5 (0.00s)
numeral_test.go:62: got 1, want 5
Apart from when it is subtractive our code assumes that every character is a
I which is why the value is 1. We should be able to re-use our ValueOf method to fix this.func ConvertToArabic(roman string) int {
total := 0
for i := 0; i < len(roman); i++ {
symbol := roman[i]
// look ahead to next symbol if we can and, the current symbol is base 10 (only valid subtractors)
if couldBeSubtractive(i, symbol, roman) {
nextSymbol := roman[i+1]
// build the two character string
potentialNumber := string([]byte{symbol, nextSymbol})
if value := allRomanNumerals.ValueOf(potentialNumber); value != 0 {
total += value
i++ // move past this character too for the next loop
} else {
total++ // this is fishy...
}
} else {
total+=allRomanNumerals.ValueOf(string([]byte{symbol}))
}
}
return total
}
When you index strings in Go, you get a
byte. This is why when we build up the string again we have to do stuff like string([]byte{symbol}). It's repeated a couple of times, let's just move that functionality so that ValueOf takes some bytes instead.func (r RomanNumerals) ValueOf(symbols ...byte) int {
symbol := string(symbols)
for _, s := range r {
if s.Symbol == symbol {
return s.Value
}
}
return 0
}
Then we can just pass in the bytes as is, to our function
func ConvertToArabic(roman string) int {
total := 0
for i := 0; i < len(roman); i++ {
symbol := roman[i]
if couldBeSubtractive(i, symbol, roman) {
if value := allRomanNumerals.ValueOf(symbol, roman[i+1]); value != 0 {
total += value
i++ // move past this character too for the next loop
} else {
total++ // this is fishy...
}
} else {
total+=allRomanNumerals.ValueOf(symbol)
}
}
return total
}
It's still pretty nasty, but it's getting there.
If you start moving our
cases[:xx] number through you'll see that quite a few are passing now. Remove the slice operator entirely and see which ones fail, here's some examples from my suite=== RUN TestConvertingToArabic/'XL'_gets_converted_to_40
--- FAIL: TestConvertingToArabic/'XL'_gets_converted_to_40 (0.00s)
numeral_test.go:62: got 60, want 40
=== RUN TestConvertingToArabic/'XLVII'_gets_converted_to_47
--- FAIL: TestConvertingToArabic/'XLVII'_gets_converted_to_47 (0.00s)
numeral_test.go:62: got 67, want 47
=== RUN TestConvertingToArabic/'XLIX'_gets_converted_to_49
--- FAIL: TestConvertingToArabic/'XLIX'_gets_converted_to_49 (0.00s)
numeral_test.go:62: got 69, want 49
I think all we're missing is an update to
couldBeSubtractive so that it accounts for the other kinds of subtractive symbolsfunc couldBeSubtractive(index int, currentSymbol uint8, roman string) bool {
isSubtractiveSymbol := currentSymbol == 'I' || currentSymbol == 'X' || currentSymbol =='C'
return index+1 < len(roman) && isSubtractiveSymbol
}
Try again, they still fail. However we left a comment earlier...
total++ // this is fishy...
We should never be just incrementing
total as that implies every symbol is a I. Replace it with:total += allRomanNumerals.ValueOf(symbol)
And all the tests pass! Now that we have fully working software we can indulge ourselves in some refactoring, with confidence.
Here is all the code I finished up with. I had a few failed attempts but as I keep emphasising, that's fine and the tests help me play around with the code freely.
import "strings"
func ConvertToArabic(roman string) (total int) {
for _, symbols := range windowedRoman(roman).Symbols() {
total += allRomanNumerals.ValueOf(symbols...)
}
return
}
func ConvertToRoman(arabic int) string {
var result strings.Builder
for _, numeral := range allRomanNumerals {
for arabic >= numeral.Value {
result.WriteString(numeral.Symbol)
arabic -= numeral.Value
}
}
return result.String()
}
type romanNumeral struct {
Value int
Symbol string
}
type romanNumerals []romanNumeral
func (r romanNumerals) ValueOf(symbols ...byte) int {
symbol := string(symbols)
for _, s := range r {
if s.Symbol == symbol {
return s.Value
}
}
return 0
}
func (r romanNumerals) Exists(symbols ...byte) bool {
symbol := string(symbols)
for _, s := range r {
if s.Symbol == symbol {
return true
}
}
return false
}
var allRomanNumerals = romanNumerals{
{1000, "M"},
{900, "CM"},
{500, "D"},
{400, "CD"},
{100, "C"},
{90, "XC"},
{50, "L"},
{40,